0=1800-360x+12x^2

Solution for 0=1800-360x+12x^2 equation:

0=1800-360x+12x^2

We move all terms to the left:

0-(1800-360x+12x^2)=0

We add all the numbers together, and all the variables

-(1800-360x+12x^2)=0

We get rid of parentheses

-12x^2+360x-1800=0

a = -12; b = 360; c = -1800;
Δ = b2-4ac
Δ = 3602-4·(-12)·(-1800)
Δ = 43200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{43200}=\sqrt{14400*3}=\sqrt{14400}*\sqrt{3}=120\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(360)-120\sqrt{3}}{2*-12}=\frac{-360-120\sqrt{3}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(360)+120\sqrt{3}}{2*-12}=\frac{-360+120\sqrt{3}}{-24}
$